(x+9)(x-3)=(x=1)^2

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Solution for (x+9)(x-3)=(x=1)^2 equation: 



(x+9)(x-3)=(x=1)^2

We move all terms to the left:

(x+9)(x-3)-((x)=0

We multiply parentheses ..

(+x^2-3x+9x-27)-(x=0

We get rid of parentheses

x^2-3x+9x-(x-27=0

We add all the numbers together, and all the variables

x^2+6x-(x-27=0

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